List customer and product without sales hackerrank sql server oracle I do not own or make these questions. Customers using Oracle Recruiting source better quality candidates, improve time to hire, and reduce recruiting expenses. From the MS docs "For stored procedures that contain several statements that do not return much actual data, this can provide a significant performance This query joins the Sales and Products tables on the product_id column, groups the results by product name, and calculates the total sales revenue for each product. 0 Several of the answers above will work around the lack of a direct reference to a specific row, but will not work if changes occur to the other rows in a table. Invoice I INNER JOIN dbo. product_name, Coalesce((ii. The above logic works with or without time components. PRICE DESC I assume that you use SQL Server, this is why I use TOP 1. name = 'MyTableName' -- table columns information select schema_name(t. The total column was done by a friend and works as expected. Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; SQL Server: Show a list of Customers that have more Orders than a specify Customer. rf, ttc. Customer_spending. invoice_id = i. id INNER JOIN Customer CU ON CU. sales, last_month. id = cu. country_name, Ci. Again, this is a rank-without-ties query. product_id = p. name as TableName, TYPE_NAME(t2. Using the UNION operator, return a si the following solution for oracle is adopted from this source. value), 0) total_value FROM Customers a LEFT JOIN Orders b ON a. Butter 3. CREATE TABLE #orders(OrderId int identity(1,1), CustNum int, Orderdate date) -- using system columns to populate demo data (I'm lazy) INSERT INTO #orders(CustNum,Orderdate) SELECT system_type_id, DATEADD(month,column_id*-1,GETDATE()) FROM sys. - DaveSV/HackerRank-SQL-Intermediate-Certificate The explanation section of the problem states: The results of the second query are ascendingly ordered first by number of names corresponding to each profession (2 <= 2 <= 3 <= 3), and then alphabetically by profession (doctor <= singer, and actor <= professor). Name, COUNT(b. - Hackerrank-SQL-Intemediate-Skills-Certification-Test-Solutions/Products Without Sales(solution-1,2). am, tg. ODCI*LIST types as they can hold 32767 items but it is a limitation on SQL functions that their expression list can have a maximum of 999 arguments. No need to get emotional about it. columns t2 on t2. you have to specify a maximum length of the list (100 in the sample query below). Getting java. product_name, ROUND(sum(ii. Solved. I tried below query and it worked for me. , This is a SQL query to get the total amount spent on each product in each city. By detailing sales figures per city and identifying customers who spent 25% or less than This works for Oracle PL/SQL. [ In this video I am solving the intermediate Certification Skills Test on Hackerrank. In other words, I want to select all customers from the customer table where there is no entry for their customer number in the invoice table. I'm trying to calculate the total purchase amount of each customer from the database available online on W3 Schools. Status. Oracle isn't the problem Created an ODBC connection to the database on the Oracle server on this machine; Restarted MS SQL Server; Created a linked server (Microsoft OLEDB Provider for ODBC Drivers) in the SQL instance; When connecting to the SQL Server using sqlcmd on this machine (I did not install SSMS there), I can query the linked database using OPENQUERY(). invoice_id and ii. 1. Watch also my other videos for more SQL Certification Solutions. This makes it portable to MySQL for example. The syntax for foreign keys is the same in Oracle and SQL Server. The tables I'm using are: Customers. Clarification: I want a row for each possible month/product tuple. Create System DSN to Oracle database on SQL Server. id and ii. This arrangement allows multiple columns of IMAGE or Problem. month and now that i think of it SQL Server 2005 has You signed in with another tab or window. SELECT customer_name, COUNT(DISTINCT product_ID) as products_count FROM customer_table INNER JOIN orders_table ON customer_table. It focuses solely on offering correct answers for SQL queries, joins, and aggregations, helping users pass the certification efficiently. This is a new question Hackerrank has added for the advance level SQL certification. id = ii. There are many factors that determine how the database resolves the query, object statistics, SYS schema statistics, and parameters, as well as server performance. - adminazhar/-hackerrank-SQL-intermediate-skills-certification-test-solution Join over 23 million developers in solving code challenges on HackerRank, one of the best ways to prepare for programming interviews. But let say I only want to show the the city/cities where someone has done at least 2 orders, and that there are two customers living in this city/cities, so what I want to do is to pick out the city/cities where a customer has made at least 2 orders, but then show the Actions. Download Sample Files. city_id = CI. Sql skills are transferrable across most databases. com” instead of no-reply@client-DomainName. SQL query for overview of purchased products per user. SQL : Select the latest sale for each product. But you need to add a terminating / after your code, on a line on its own - Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; T-SQL Challenges from hackerrank. Print Prime Numbers. To me learning pl/sql or t/sql is no different than learning any other programming language and you’re always learning something new. It showcases my growth, challenges faced, and solutions offered. sql & 2. SELECT CUSTOMER_NAME, Y. Step 1: Install Oracle ODBC drivers on server. While you can have Accounting and Marketing schemas, they are not tightly-coupled to individual users. You are viewing a single comment's thread. This repository contains all solutions and "thought process" to Hackerrank's SQL challenges. units_sold, this_month. In Microsoft SQL Server, a pointer to the IMAGE or TEXT data is stored with the rows in the table while the IMAGE or TEXT data is stored separately. Fund open source developers The ReadME Project. Contribute to ejaj/SQL development by creating an account on GitHub. customer_ID, customer_name HAVING COUNT(DISTINCT product_ID) > 10 Verify your SQL Skills. I could set this query up in one Oracle database and make it run slow and make it run fast in another. Ask Question Asked 7 years, 10 months ago. tables t where t. id group by c. Automate any workflow Oracle schemas are like My Documents folders in the Windows OS. I've not used SQLfiddle much so I wasn't able to setup a test schema for this (yet). Medium SQL (Intermediate) Max Score: 30 Success Rate: 96. id (category="product") Name: customer. The database is SQL Server 2008 R2. country_id = CO. Customers also increase uptime for Oracle applications by running them on any Oracle server and Java applications run 2X faster on Oracle SPARC servers using unique, built-in accelerators. Customer Spending. All customers who do not have an invoice All products that were not sold Category: Is this related to "customer" or "product"? Print "customer or "product" ID: Customer. dual is an in-memory table. Customer GROUP BY a. We segment the hosted information on Oracle customers comprehensively Join over 23 million developers in solving code challenges on HackerRank, one of the best ways to prepare for programming interviews. The EMPLOYEES table and the SALES_DEPT table contain the following columns: The customers should be listed alphabetically beginning with the letter 'A', and their corresponding order totals should be sorted from the highest amount to the lowest amount . Products. The OCCUPATIONS table is described Contains solved queries for the Hackerrank SQL (Intermediate) Skills Certification Test 🎓. city_name, pr. Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; I can do this on a calculator without any problems but writing the SQL is a different story. The output column headers should be Doctor, Professor, Singer, and Actor, respectively. sql sql-server hackerrank sql-query sqlserver So, after reading some other materials and trying a few different things, I think I have a correct query. coalesce is supported in both Oracle and SQL Server and serves essentially the same function as nvl and isnull. ORDER_ID = O. id If you want all customer and product combinations, then I would suggest: select c. Please check 1. txt at main · mahedei/Hackerrank-SQL-Intemediate-Skills-Certification-Test-Solutions SQL. Customer) totalOrders, COALESCE(SUM(b. I have an Oracle 11g XE database that I would like to transfer into SQL Server Express 2005. We use cookies to ensure you have the best browsing experience on our website. Please check 1. Curd Now, 2000(Year) contains number of sales. price = b. nb: using dense_rank also allows for "top n per" result, e. name as TableName, t. I need to use the Adventurewalks2017 database for thisagain. Leaderboard. * from sys. product_name FROM product WHERE product. Many thanks, Mike SQL (Intermediate) It includes complex joins, unions, and sub-queries. – How to Earn SQL (Advanced) Certification on Hackerank ? In this video, you'll learn how to earn free certification from Hackerrank*****Impor In standard SQL, you would write: SELECT customer_num, COUNT(*) FROM AllOrder GROUP BY customer_num ORDER BY COUNT(*) DESC FETCH FIRST 1 ROW ONLY; This aggregates the data by customer, counting the number of orders. Can anyone help? There were a number of contests where participants each made number of attempts. It will be updated everyday. category AND a. Data Two tables: Customers and Orders. 2 IMAGE and TEXT Data Types (Binary Large Objects). e. In general, I would not suggest using these legacy views unless you absolutely need to backport your These concepts introduce more complex features and functionalities of SQL. Now, Now, the question is to find the product with highest number of sales. Here's their snippet that won't seem to run for me in Chrome. The columns are: Customer name, Year, Month, and Revenue. 50%. fn_table_numbers( numini integer, numfin integer, exponencial integer default 0 ) return tbl_numbers is numeros tbl_numbers; indice number; begin numeros := tbl_numbers(); for i in ( with tabla as (select numini, numfin from dual) select numini num from tabla union all select You'll have to omit those records in the addition which don't belong to a full week. sales, last_year. year in (2008,2007) group by fill. Oracle also has a number of legacy data dictionary views-- TAB, DICT, TABS, and CAT for example-- that could be used. Surprisingly it does seem to understand PL/SQL; and even more surprisingly it handles the set serveroutput on, which is a SQL\Plus/SQL Developer client command. challenge_id" could Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI here's some code that should work in SQL Server, Oracle, or MySQL: SELECT current_timestamp - CAST(d1. sale_id, p. 66%. 1 SQL Query and Information about Sales Order Line Number ; Oracle Script to Copy Responsibilites of one user account to another user account Emails generated by Oracle ERP are delivered to customer/Supplier with from email address as “no-reply@oracle. You signed out in another tab or window. You signed in with another tab or window. We use cookies to Link to SQL Code on GitHub: The goal of this project is to analyze data from a sales records database for scale model cars and extract information for decision-making. Join over 23 million developers in solving code challenges on HackerRank, one of the best ways to prepare for programming interviews. SELECT first_name from customers WHERE first_name not in (select first_name from customers join orders on customers. You can toss a subquery in your WHERE clause to find customers that have had sales today:. 7. The below makes two passes of the data, but returns correct results in each case. sql. Please append a semicolon "" at the end of the query. 400 4. You'll notice some extra stuff in there to test if the sign of the row is negative. product_id = pr. Depending on the employer’s technical interviewing tool, candidates can choose from a range of relational database tools, including DB2, MySQL, Oracle, and MS SQL Server. create or replace function [schema]. I was not able to solve it at all. CREATE TABLE products_sold ( product_id numeric(10) not null, 2 List Customer and Product Without Sale Using the UNION operator in one list return all customers who do not have an invoice and all products that were not sold For each customer without an invoice return - the string customer - the customer id - the customer name 2 For each product without an invoice return - the string product - the product id - the product name 4 The Install Oracle ODBC drivers on SQL Server. You can break this answer by switching the orders for customers 102 and 103. Oracle supports operating systems such as Windows, Linux, Solaris, HP-UX, OS X, etc. ID = b. Using the UNION operator, return a single list that includes all customers who do not have an invoice and all products that were not sold. Question Find customers who have never made an order. TransactionDate, I. be/35gj How can I achieve the following in oracle without creating a stored procedure? Data Set: question_id element_id 1 7 1 8 2 9 3 10 3 You signed in with another tab or window. country_name,CI. WITH CTE AS( SELECT DISTINCT CO. This is appears to be a query that can be solved with relational division and one way to achieve that is by utilizing nested NOT EXISTS queries. : enclosed in parentheses). [PS]. customer_name, p. sales and see if those three sales numbers are correct. SELECT count(*) /*count of transactions*/ FROM transactions WHERE /*Transactions in the last two months*/ transaction_date > DATEADD(mm, -2, GETDATE()) /*For customers that have had a sale today*/ customer_number in (SELECT customer_number List Customers and Products Without Sales Enter your query below. Note: Print NULL when there are no more names corresponding to an Given a sales table with sales amount stored in local currencies and an exchange rate table containing currency conversion rate, to get total sales amount in USD for each sales date I need query Ironically Oracle owns MySql. ORDER_DATE <= DATEADD(year, 10, (SELECT MIN(ORDER_DATE) FROM ORDERS)) ORDER BY O. SELECT Customer , Month , COUNT(ReceiptNo) AS Visits , SUM(Revenue) AS Revenue FROM (SELECT customer_first_name || ' ' || customer_middle_initial || '. customer_id LEFT JOIN invoice_item ii ON ---- Products Without Sales (solution_1) SELECT product. SELECT Distinct Name FROM Production. SELECT C. Sep 25, 2023 Marco Russo & Alberto Ferrari Power Pivot, and SQL Server Analysis Services. Submissions. Business Expansion. *[^aeiou]$','i') and regexp_like(city,'^[^aeiou]\\w+[^aeiou]$','i'); . here I want to combine the first and last names in the new column, which is the full name so I'm using CONCAT. Output the first name of the customer. digit as int) FROM ( SELECT digit FROM ( select '1' as digit union select '2' union select '3' union I had a simil issue. product_name, coalesce(sum(ii. sql and 2. 06%. Unzip the packages to a local directory on the SQL SQL query: SELECT Name_Seller, Month, Value FROM SALES WHERE Value = (SELECT MAX(Value) FROM SALES GROUP BY Name_Seller); List customers who sold most in mssql. PRICE FROM CUSTOMERS C INNER JOIN ORDERS O ON C. the basic idea is to exploit oracle's hierarchical queries. product_id; Output: Consider two non-negative long integers, and , where . Milk 2. Concat is an SQl server function that takes a variable number of string arguments and concatenates (JOIN) them into a single string. You can easily perform UNION with both the SQLs. city_id and cu. Note: Print NULL when there are no more names corresponding to an occupation. i created an oracle function that returns a table of numbers. Top Competitors. ID WHERE O. TotalScore I have the following SQL statement that shows the total sales amount for customers in cities who have done at least 2 orders. [SQL] Using Oracle in HackerRank question, largest and smallest city name. Problem. customer_ID GROUP BY customer_table. 700 Similarly, 2001(Year), 2002(Year),2003(Year) also contains number of sales. Customers achieve breakthrough performance, cost efficiencies, and security for business-critical workloads with Oracle servers. 3. Msg 4104, Level 16, State 1, Server WIN-ILO9GLLB9J0, Line 9 The multi-part identifier "Challeneges. schema_id)+'. select d. 7 Advanced SQL Interview Questions. id (category="customer") or product. You need to make sure that the Data Source is an alias that the tnsnames file knows about (on the server where SQL Server resides, regardless of where you're running the queries from); SQL Server is going to be just like any other Oracle client and needs to know where to connect to and without the tnsnames. ) This article analyzes the performance of different DAX techniques to identify any products without sales in an area or a time period. We then apply SUM() to calculate the total sales for each month, and group the results by year and month. product_name; You're missing the ON keyword and there is the additional issue that in Oracle dates always have the components year, month, day, hour, minute and second and (assuming the NLS_DATE_FORMAT session parameter allows a valid cast from a string to a date) then '2017-12-31' will be converted to 2017-12-31T00:00:00 and your query will not select values that are SQL : List Customer And Product Without SaleTo Access My Live Chat Page, On Google, Search for "hows tech developer connect"I have a hidden feature that I pr Oracle supports the DATE keyword for introducing date constants using ISO-standard, unambiguous, non-locale-specific formats. This repository contains MySQL solutions of the HackerRank-SQL-Intermediate-Certificate problems which I encountered during the test. Medium SQL (Intermediate) Max How to Earn SQL (Advanced) Certification on Hackerank ? In this video, you'll learn how to earn free certification from Hackerrank*****Impor This intermediate SQL solution provides insights into product sales across cities, offering a comprehensive overview of customer spending patterns. It then orders them by the number descending and chooses the first row -- the customer with the most orders. Some editing is likely required to make it run on Oracle. with gen as ( select 1 as cust_id, (date '2020-01-10') + 1 as q from dual union all select 1, (date '2020-01-10') + 2 as q from dual union all select 1, (date '2020-01-10') + 3 as q How can we rewrite this SQL query without IN clause [also without rownumber concept in use], as ORACLE is having restriction for IN clause. Id (Category="Customer") Or That documentation suggests that the command only has effect when executing a statement at the SQL*plus prompt. it is wrong i Could you modify the first line of the select statement to: SELECT product, this_month. Write a query that prints a list of employee names (i. id GROUP BY CO. rownum_rf, count(*) count_rfm, Users select their countries from a list I give to them, but the list is really huge so it would be great to have a SQL query that can avoid using that list, that is look in the DB and give back only those countries which are in the database, because for example I have nobody from Barbados, even if I have that option in the country select field Solved queries for the Hackerrank SQL (Intermediate) Skills Certification Test 🎓. For example: AnActorName(A), ADoctorName(D), AProfessorName(P), and ASingerName(S). line_total_price), 2) as tot from city ci, customer cu, invoice i, invoice_item ii, product pr where ci. We use cookies to ensure you have the best browsing Try this one if you want to get the whole row, (supports most RDBMS)SELECT a. Sqlserver vs. quantity), 0) AS quantity FROM customer c LEFT JOIN invoice i on c. ________ I have got the query working to pull customers monthly revenue from all the years for which the data is present. sku, product. customer_name (category="customer") or product. My current query gives me the product wise purchase amount for the customer. The Oracle Cloud offers all the services you need to migrate, build, and run your IT, from existing enterprise workloads to new cloud-native applications and data platforms. Solve Challenge. At first I thought I'd just generate the tables in Oracle as SQL, manipulate the data formats, and run the query in SQL Server. I had to write a particular query in a framework that write query by itself. Query the number of ocurrences of each Hackerrank Intermediate SQL certification solutions with basic SQL quarries, Sub quarries and Aggregation functions. id = i. Orders. Oracle SQL specifically. id NOT IN (SELECT product_id FROM invoice_item); ----- Products Product GitHub Copilot. id group by The only one's this question deals with is the Customers table (stores customer details), the ProductSales table (store details about each product sale, and HairCuts table, store details about each cut. The result includes the names of the city and product, as well as the total amount spent on the product, rounded to 2 decimal places. My solution: WITH MaxScores AS ( SELECT Hacker_ID, Challenge_ID, MAX(Score) AS MaxScore FROM Submissions GROUP BY Hacker_ID, Challenge_ID ), SummedScores AS ( SELECT Hacker_ID, SUM(MaxScore) AS TotalScore FROM MaxScores GROUP BY Hacker_ID ) SELECT S. Name To further gain more knowledge about joins, kindly visit the link below: Visual Representation of SQL Joins; Result, i do this select distinct city from station where regexp_like(city,'^[^aeiou]. Write better code with AI Security. object_id Here is the first solution, which could be used as a working base. In SQL Server SET NOCOUNT affects the behaviour even in non-interactive scenarios. MS SQL Server's schemas are namespaces. Name, S. Medium SQL (Intermediate) Max Solved queries for the Hackerrank SQL (Intermediate) Skills Certification Test 🎓. List all sales along with the corresponding product names. Find and fix vulnerabilities Contains solved queries for the Hackerrank SQL (Basic) Skills Certification Test 🎓. The fact that Oracle has a feature that SQL Server does not seems to generate all kinds of reactions towards the disputable characteristics of this feature. Once upon a time, dual had two records (hence the name) and was intended to serve as a dummy recordset to duplicate records being joined with. Category ,fill. 1. PSDBOWNER SQL SERVER Name: X I tried below query in my SSMS select * from [X]. SalesOrderDetail SOD on SOD. ora file, it's not going to know the List Customer And Product Without Sale In One List Return, All Customers Who Do Not Have An Invoice And All Products That Were Not Sold. id=orders. 0. You switched accounts on another tab or window. * FROM tbProduct a INNER JOIN ( SELECT Category, MAX(Price) maxPrice FROM tbProduct GROUP BY Category ) b ON a. Easy SQL (Advanced) Max Score: 25 Success Rate: 97. : the name attribute) from the Employee table in alphabetical order. Thomson Data offers just that. Joining the subquery result to product table reduces the rows involved in that join. SELECT c. Create linked server on SQL server using System DSN. Medium SQL (Advanced) Max Score: 40 Success Rate: 93. 2. Use The UNION Operator In This Query. Marco and Alberto have worked with Analysis Services, Power BI and Power Pivot since the first Optimized for Oracle software. object_id = t. If I understand correctly, you are looking for the top 50 sales for customers based on 2011 data - and want to see all years data for those top 50 from 2011, regardless of those customers being in the top 50 for other years. Finding the best selling item for each of your best customers in SQL. ProductID = P. name from ( select substr( csv , instr(csv,',',1,lev) + 1 , instr(csv,',',1,lev+1 )-instr(csv,',',1,lev)-1 ) lstid from (select ','||'1,2,3,4,5'||',' csv from dual Watch all Easy Hackerrank SQL Problems solved in this video. List the top 1 customer's transactions who have the highest total transaction amount in such a way that the result shows all the transaction done by the customer and the last row shows the total amount of all the transaction done by the customer. This article talks about performing relational division in SQL in great detail and helped to clear things up a lot for me, Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; Oracle Setup: CREATE TABLE sales ( "DATE", Store, Sales ) AS SELECT DATE '2015-01-01', 'St01', 12123 FROM DUAL UNION ALL SELECT DATE '2015-01-01', 'St02', 3123 FROM DUAL UNION ALL SELECT @VasinYuriy That is not a limitation of the SYS. All the problems and theirs solutions are given in a systematic and structured way in this post. com; Oracle ERP Cloud SQL Query to find Bank SELECT a. Below are seven examples of the kinds of problems a data scientist or software engineer might face during a technical interview. Ask Question Asked 7 years, 10 Line 12 Invalid column name 'challenges_created'. Business_expansion. tables t inner join sys. Unsolved. product_name (category="product") Tables: Customer. product_name FROM Sales s JOIN Products p ON s. 15%. But I'm struggling to figure out how to get highest revenue month-year from this data. – Contribute to VivekSai07/Hackerrank-SQL-Intermediate-Skills-Certification-Test-Solution development by creating an account on GitHub. Medium SQL (Intermediate) Max Score: 30 Success Rate: 97. Find and fix vulnerabilities Actions Customer Stories Partners Executive Insights Open Source GitHub Sponsors AmareshMuddebihal / HackerRank-SQL List Customer and Product Without Sale Using the UNION operator, in one list return all customers who do not have an invoice and all products that were not sold. category = b. system_type_id) as DataType, t2. Using the dual table is a good practice. 300 3. ORACLE database : Y ORACLE table name : PS. Download the necessary Oracle Instant Client packages: Basic, ODBC, and SQL*Plus (optional) b. sql sql-server oracle hackerrank oracle-database hackerrank Generate the contest leaderboard. OrderDetails. Considering your data model and requirements, you should try the below SQLs. SQL (Basic) SQL Product Actions. Discussions. lstid , t. g. Basic Join. rfm, tg. Easy SQL (Intermediate) Max Score: 30 Success Rate: 94. They are essential for building more sophisticated and robust queries, managing data relationships, and optimizing query performance. CustomerID WHERE EXISTS(SELECT 1 FROM Invoice WHERE CustomerID = I. I am trying to generate results that show all customers that are in the customer table that have never placed an order and will therefore have no entry on the invoice table. QNTY FROM CUSTOMER_T CUST, ( The question title is not very helpful. A common use of Oracle's ROWID is to provide a (somewhat) stable method of selecting rows and later returning to the row to process it (e. [Y]. Google SQL Interview Question:https://youtu. NAME, O. GitHub community articles Products Without Sales(solution I have an attendance table for the employees like the following ID Employee-ID Date Coming-time Leaving-time Break(in hours) 1 1 2016-01-01 08:00:00 18: This repository contains MYSQL solutions of HackerRank-SQL-Intermediate-Certificate problems which I encountered during the test . I can list them all but not just the ones I want, might not understand Rank(), ROW_NUMBER(), FIRST_VALUE use in Oracle. With HackerRank and Oracle Recruiting, customers can standardize their global technical recruiting The quickest path to approach companies that use Oracle lies in incorporating target-specific information into promotional efforts. So, prior to summing up, you'll have to find the min and max of the dates, manipulate them such that they form "whole" weeks, and then run your original query with a WHERE that limits the date values according to the new range. InvoiceTotal FROM dbo. Whereas SQL Server supports only windows and Linux operating systems. Calculating Sales Count. Focus on standard sql and you know enough for most companies . This collection provides solutions to the HackerRank SQL Certification Test problems. customer_ID = orders_table. Explore my GitHub repository to learn from my experiences and find Let's say we have a Product table (product_id, product_name) and a Sales table (product_id, date, qty, amount). Sales. Welcome to CarrY4U Product GitHub Copilot. Customer Relationship Management (CRM) Information Technology We use both Oracle and Microsoft SQL Server for our entire product line, using the best features of each of them to solve SELECT TOP 1 C. Learn more about Foreign Keys. Query: SELECT s. Accelerate your Job Search. Tested it on SQL Server - works fine. Try this:-- custom table information select schema_name(t. ProductID LEFT JOIN I believe the following query should work to identify the customer name with the highest amount derived from all orders in the current calendar year:. Print NA for null customers or product or null quantity . Need to get MAX selling price in last 4 transaction. For starters, the question was in the style: there is this feature in Oracle that is being missed in SQL Server and what is the recommended approach. sql files for the solutions I submitted! I do not think this answer is correct, although it does produce the correct result. If we want to find the total count of sales for each month (instead of the total sales amount), replace the This T-SQL query SELECT city, Len(city) FROM station ORDER BY Len(city) returns table sorted by city, not by Len(city) - is this proper behavior? Hackerrank SQL challenge. Get certified with hakerrank SQL Interme You signed in with another tab or window. 2821 verified user reviews and ratings of features, pros, cons, pricing, support and more. customer_id and i. That is my criteria for which answers fall technically short. Input Format. maxPrice Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. digit + d2. The bitwise AND of all long integers in the inclusive range between and can be expressed as , where is the bitwise AND operator. The result is ordered by The easiest way would be to specify. That site doesn't seem to ever show your the output from your submission, unhelpfully, but does with just 'run code'. Example 1 without empty rows: product ,year ,month from sales --this ideally would be from a products table cross join tm where year in (2008,2007)) fill where fill. Paneer 4. Based on his total column, I've added the Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. Product P LEFT JOIN Sales. Binary Tree Nodes. quantity), 0) as quantity from customer c cross join product p left join invoice i on c. Hopefully it's not a big difference but I suspect at least the CASE statement isn't the same on Oracle. If you don't select DUMMY from it, it uses a special access path (FAST DUAL) which requires no I/O. digit + d3. Skills. What I need is the total purchase amount. Example here:. What sql query would return the monthly sales per product, and include products with no sales? (I'm using sql server if that makes any difference). Given pairs of long integers, and , compute and print the bitwise AND of all natural numbers in the inclusive range between and . ID, a. - mahedei/Hackerrank-SQL-Intemediate-Skills-Certification-Test-Solutions Customer Stories Partners Executive Insights Open Source GitHub Sponsors. _____ SUBSCRIBE!Do you want to understand how to solve SQL My journey of earning a SQL certification and tackling HackerRank SQL challenges. Compare Oracle Database vs Microsoft SQL Server. The problem is that customer 102 only has 1 order (both records are orderId 9), but this subselect will treat customer 102 as having 2 orders. Hacker_ID, H. Customer C ON I. select am, rf, rfm, count_rf, count_rfm, rownum_rf, rownum_rfm from ( -- next join the top 10 products to the data again to get -- the subproduct counts select tg. The query should return all customers ,even customers without invoices and also products,even those products that were not sold. Seems to be a little bit simpler. New Companies. Modified 2 years, Cannot reproduce this behavior in SQL Server 2016 - works as anyone would have guessed patients is the table name which has the first name and last name column. Oracle is the only technology provider with a complete suite of integrated cloud applications and a cloud infrastructure platform. '+t. Order by Sales Data for all customers and products. 200 2. a. The physical and logical storage methods for IMAGE and TEXT data differ from Oracle to Microsoft SQL Server. CustomerName, I. CustomerID = C. This intermediate SQL solution provides insights into product sales across cities, offering a comprehensive overview of customer spending patterns. Please note, each year contains number of sales that products has made. I used the table (values('x')) DUAL(DUMMY) to retrieve the result from a query that has a single column with an ANY result (in bold what writes the framework, in italic what I put as parameter): SELECT CASE WHEN 'X' = ANY (SELECT COLUMN FROM TABLE) THEN 1 Explanation: In this query, we use the YEAR() and MONTH() functions to extract the year and month from the Order_date column. Automate any workflow Solution for some HackerRank challenges by SQL Server. CustomerID GROUP BY CustomerID HAVING COUNT(*) > 1) And another way for SQL Server 2005+: Below is the code in a SQL statement for SQL Server. 99%. count_rf, tg. ' || I linked ORACLE Database in my local sql server called X. . cust_id) Oracle Products, Solutions, and Services. The return type for isnull matches the type of the first argument, that is not true for coalesce, at least on SQL Server. You can construct and populate a list in PL/SQL with more than 1000 items and pass it to the SQL statement and it will work db<>fiddle and you can pass more than 1000 select ci. sql hackerrank sqlserver hackerrank-solutions hackerrank Code Issues Pull requests Códigos em SQL (Oracle e MS Server), para aprendizado e referência. List Customer and Product Without Sale Using the UNION operator, in one list return all customers who do not have an invoice and all products that were not sold. In neither of the solutions do you guarantee to generate the results with the correct ordering. Return 3 Values: - Category - Is This Line Related To "Customer" Or "Product"? Print "Customer" Or "Product" Without Quotes. For example, if and , the calculation is . Ask Question Asked 3 years, 5 months ago. SQLSyntaxErrorException: ORA-01795: maximum number of expressions in a list is 1000 for above expression. SELECT productid FROM product where purchase_date > sysdate-30; Remember this sysdate above has the time component, so it will be purchase orders newer than 03-06-2011 8:54 AM based on the time now. By detailing sales figures per city and identifying customers who spent 25% or less than the average, this solution aids in strategic decision-making for optimizing sales and customer engagement. List all the customer IDs and last names who have made more than 2 orders. (SELECT *, 'Top 10' FROM sales ORDER BY sales_amount DESC LIMIT 5) UNION (SELECT *, 'Bottom 10' FROM sales ORDER BY sales_amount ASC LIMIT 5) ORDER BY sales_amount DESC; which gives the required result, without CTEs. GitHub - MahedeiHasan/Hackerrank-SQL-Intemediate-Skills-Certification-Test-Solutions: Solved queries for the Hackerrank SQL (Intermediate) Skills Certification Test 🎓. Return to all comments → Among several electronic database Management System, the 2 most well-liked and widely used are Oracle and SQL Server. Reload to refresh your session. First SQL returns this list –> All customers who do not Hello coders, in this post you will get all the solution of HackerRank SQL Solutions. Input Format The Employee table containing employee data for a company is described as follows: You can use two window functions to calculate difference between consequtive dates and sliding window with ROWS offset to count distinct preceiding consequtive days. - Id - Customer. A user can grant permissions to other users to see things in their schema but an Oracle schema is essentially a user's workspace. No, in Oracle there is no SELECT without FROM. (There are some important differences, coalesce can take an arbitrary number of arguments, and returns the first non-null one. city_name,COUNT(city_id) AS cnt , AVG(COUNT(city_id)) OVER() avg_cnt FROM COUNTRY CO INNER JOIN City CI ON CI. Generate the following two result sets: Query an alphabetically ordered list of all names in OCCUPATIONS, immediately followed by the first letter of each profession as a parenthetical (i. all_columns -- In this video we will discuss an SQL interview question that was asked in meesho's HackerRank online test. customer_id left join invoice_item ii on ii. Don't use BETWEEN on dates. sql files for the solutions I submitted! Hacker Rank SQL. changing the where clause to where rnk <= 5 would list top 5 selling products per city. There are several basic variations between Oracle and SQL Server Join over 23 million developers in solving code challenges on HackerRank, one of the best ways to prepare for programming interviews. I need a query that will list the total spent on both hair cuts and products for each customer in the customers table. Question 1: Which products The following is a much better solution to the problem: WITH RankedOccupations AS ( SELECT NAME, OCCUPATION, ROW_NUMBER() OVER (PARTITION BY OCCUPATION ORDER BY NAME) AS rn FROM OCCUPATIONS ) SELECT MAX(CASE WHEN OCCUPATION = 'Doctor' THEN NAME END) AS Doctor, MAX(CASE WHEN OCCUPATION = 'Professor' The company president would like the sales listed starting with the highest amount first. city_name ) SELECT SQL Server Oracle; CREATE TABLE products_sold ( product_id numeric(10) not null, customer_id INT not null, CONSTRAINT fk_pr FOREIGN KEY (customer_id) REFERENCES customer(id) ) GO. Time components can cause the code to do things you don't expect. cphqmyday nml jzjra rramdv edhvnwphx maxidmu rmlql kkww wphy lotwsy

List customer and product without sales hackerrank sql server oracle. Example 1 without empty rows: .